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Divide the coins into a pile of 40 and a pile of 10 at random.
The heads will be divided somehow between the two piles.
N in one, and 10 - N in the other, with 0 <= N <= 10.
The original coin distribution is then
|Pile 1||Pile 2|
Flip all 10 coins in the Pile 1, and you will have
It doesn't matter what N is.